Example: 10 students of class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.
Solution. Let the number of boys be x and the number of girls be y. Then the equations formed are
x + y = 10 ....(1)
and y = x + 4 ....(2)
Let us draw the graphs of equations (1) and (2) by finding two solutions for each of the equations. The solutions of the equations are given.
x + y = 10
x + y = 10 | ||
Points | A | B |
x | 0 | 8 |
y = 10 − x | 10 | 2 |
y = x + 4 | |||
Points | C | D | E |
x | 0 | 1 | 3 |
y = x + 4 | 4 | 5 | 7 |
Plotting these points we draw the lines AB and CE passing through them to represent the equations. The two lines AB and Ce intersect at the point E (3, 7). So, x = 3 and y = 7 is the required solution of the pair of linear equations.
i.e. Number of boys = 3 and Number of girls = 7.
How to Verify your Answer: Putting x = 3 and y = 7 in (1), we get L.H.S. = 3 + 7 = 10 = R.H.S., (1) is verified.
Putting x = 3 and y = 7 in (2), we get 7 = 3 + 4 = 7, (2) is verified.
Hence, both the equations are satisfied.
Example: Half the perimeter of a garden, whose length is 4 more than its width is 36m. Find the dimensions of the garden.
Solution: Let the length of the garden be x and width of the garden be y. Then the equation formed are
x = y + 4 ....(1)
Half perimeter = 36
x + y = 36 ....(2)
x = y + 4 | ||
Points | A | B |
x | 0 | 4 |
y | −4 | 0 |
x + y = 36 | ||
Points | C | D |
x | 10 | 20 |
y = 36 − x | 26 | 16 |
Plotting these points we draw the lines AB and CD passing through them to represent the equations.
The two lines AB and CD intersect at the point (20, 16), So, x = 20 and y = 16 is the required solution of the pair of linear equations i.e. length of the garden is 20 m and width of the garden is 16 m.
Verify Your Answer: Putting x = 20 and y = 16 in equation no. (1), We get 20 = 16 + 4 = 20, (1) is verified.
Again, putting x = 20 and y = 16 in equation (2), we get 20 + 16 = 36 ⇒ 36 = 36, (2) is verified.
Hence, both the equations are satisfied.
Example: Draw the graphs of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.
Solution: Pair of linear equations are:
x – y + 1 = 0 ....(1)
3x + 2y – 12 = 0 ....(2)
x – y + 1 = 0
x – y + 1 = 0 | ||
Points | A | B |
x | 0 | 4 |
y = x + 1 | 1 | 5 |
3x + 2y – 12 = 0 | ||
Points | C | D |
x | 0 | 2 |
y = (12 –3x)/2 | 6 | 3 |
Plot the points A(0, 1), B(4, 5) and join them to get a line AB. Similarly, plot the points C(0, 6), D(2, 3) and join them to form a line CD.
Clearly, the two lines intersect each other at the point D(2, 3). Hence x = 2 and y = 3 is the solution of the given pair of equations.
The line CD cuts the x-axis at the point E (4, 0) and the line AB cuts the x-axis at the point F(–1, 0).
Hence, the coordinates of the vertices of the triangle are ; D(2, 3), E(4, 0), F(–1, 0).
Verify Your Answer:
Both the equations (1) and equation (2) are satisfied by x = 2 and y = 3. Hence, pair of equations are now Verified.
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