Example : 9A weight lifter lifted a load of 100 kg to a height of 3 m in 10 s. Calculate the following:
(i) amount of work done
(ii) power developed by him
Solution. (i) Work done is given by
W = F . s
Here, F = mg = 100 × 10 = 1000 N
W = 1000 N × 3 m = 3000 joule
(ii) Now,
, where W = 3000 J and t = 10 s
∴ P = 3000J/10s = 300 W
Example : 10A water pump raises 60 liters of water through a height of 20 m in 5 s. Calculate the power of the pump. (Given: g = 10 m/s
2, density of water = 1000 kg/m
3)
Solution. Work done, W = F.s...(1)
Here, F = mg ...(2)
But, Mass = volume × density
Volume = 60 liters = 60 × 10
–3 m
3 Density = 1000 kg/m
3 ∴ Mass , m = (60 × 10
–3 m
3) × (1000 kg/m
3) = 60 kg
∴ Equation (2) becomes
F = 60 kg × 10 m/s
2 = 600 N
Now, W = F . s = 600 N × 20 m = 12000 J
Power =
= 12000J/5s = 2400 W
Example : 11 A woman pulls a bucket of water of total mass 5 kg from a well which is 10 m deep in 10 s. Calculate the power used by her.
Solution. Given that m = 5 kg; h = 10 m; t = 10 s, g = 10 m/s
2Now,